| Calvin wrote: Quote:moviePig wrote: No, it doesn't... and here's why: In a red/blue 3D projection, the blue image is composed entirely of blue light, because its projector lens has a blue filter over it. And, naturally, what the blue projector lens passes intact (i.e., an image built of varying amounts of blue light) the blue viewer lens does as well. The red viewer lens, meanwhile, lets *no* blue light through (...and, thus, sees no "variability" to the blue light with which to construct an image). Again, this description does *not* apply to colored images on white paper in a lighted room ...where everything's more-or-less reversed... More later, but no matter how you look at the differences between settings: white paper, movie screen in the dark, TV screen in light or dark; the red filter simply does not block out blue, and the blue filter does not block out red. What gets through does not 'appear' either blue or red though, but merely some degree of dark. One minor thing should be noted. In a typical pair of red/blue glasses, the red does a better job of obscurring the red image than the blue does in obscurring the blue image. I recently bought two pair off of the internet for a dollar and a sase (ask and I'll tell you how), and the blue filters are much better than my older blues. Yes, the red filter *does* block blue... and the blue, red (...except for the leakage inherent in all systems: red/blue, polaroid, or shutter-glasses). When you say that "what gets through" merely appears as dark, that is in fact the effect of its having been blocked. Take your two pairs of glasses and put a (single) lens from one against a lens from the other... and then look through the sandwich. If you've chosen opposite colors, the light that gets through will be greatly diminished, i.e., blocked. -- /---------------------------\ | YOUR taste at work... | | | | http://www.moviepig.com | \---------------------------/ |